(0) Obligation:
Runtime Complexity TRS:
The TRS R consists of the following rules:
h(X, Z) → f(X, s(X), Z)
f(X, Y, g(X, Y)) → h(0, g(X, Y))
g(0, Y) → 0
g(X, s(Y)) → g(X, Y)
Rewrite Strategy: INNERMOST
(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)
Converted CpxTRS to CDT
(2) Obligation:
Complexity Dependency Tuples Problem
Rules:
h(z0, z1) → f(z0, s(z0), z1)
f(z0, z1, g(z0, z1)) → h(0, g(z0, z1))
g(0, z0) → 0
g(z0, s(z1)) → g(z0, z1)
Tuples:
H(z0, z1) → c(F(z0, s(z0), z1))
F(z0, z1, g(z0, z1)) → c1(H(0, g(z0, z1)), G(z0, z1))
G(z0, s(z1)) → c3(G(z0, z1))
S tuples:
H(z0, z1) → c(F(z0, s(z0), z1))
F(z0, z1, g(z0, z1)) → c1(H(0, g(z0, z1)), G(z0, z1))
G(z0, s(z1)) → c3(G(z0, z1))
K tuples:none
Defined Rule Symbols:
h, f, g
Defined Pair Symbols:
H, F, G
Compound Symbols:
c, c1, c3
(3) CdtUnreachableProof (EQUIVALENT transformation)
The following tuples could be removed as they are not reachable from basic start terms:
F(z0, z1, g(z0, z1)) → c1(H(0, g(z0, z1)), G(z0, z1))
(4) Obligation:
Complexity Dependency Tuples Problem
Rules:
h(z0, z1) → f(z0, s(z0), z1)
f(z0, z1, g(z0, z1)) → h(0, g(z0, z1))
g(0, z0) → 0
g(z0, s(z1)) → g(z0, z1)
Tuples:
H(z0, z1) → c(F(z0, s(z0), z1))
G(z0, s(z1)) → c3(G(z0, z1))
S tuples:
H(z0, z1) → c(F(z0, s(z0), z1))
G(z0, s(z1)) → c3(G(z0, z1))
K tuples:none
Defined Rule Symbols:
h, f, g
Defined Pair Symbols:
H, G
Compound Symbols:
c, c3
(5) CdtGraphRemoveDanglingProof (ComplexityIfPolyImplication transformation)
Removed 1 of 2 dangling nodes:
H(z0, z1) → c(F(z0, s(z0), z1))
(6) Obligation:
Complexity Dependency Tuples Problem
Rules:
h(z0, z1) → f(z0, s(z0), z1)
f(z0, z1, g(z0, z1)) → h(0, g(z0, z1))
g(0, z0) → 0
g(z0, s(z1)) → g(z0, z1)
Tuples:
G(z0, s(z1)) → c3(G(z0, z1))
S tuples:
G(z0, s(z1)) → c3(G(z0, z1))
K tuples:none
Defined Rule Symbols:
h, f, g
Defined Pair Symbols:
G
Compound Symbols:
c3
(7) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
G(z0, s(z1)) → c3(G(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:
G(z0, s(z1)) → c3(G(z0, z1))
The order we found is given by the following interpretation:
Polynomial interpretation :
POL(G(x1, x2)) = [5]x2
POL(c3(x1)) = x1
POL(s(x1)) = [1] + x1
(8) Obligation:
Complexity Dependency Tuples Problem
Rules:
h(z0, z1) → f(z0, s(z0), z1)
f(z0, z1, g(z0, z1)) → h(0, g(z0, z1))
g(0, z0) → 0
g(z0, s(z1)) → g(z0, z1)
Tuples:
G(z0, s(z1)) → c3(G(z0, z1))
S tuples:none
K tuples:
G(z0, s(z1)) → c3(G(z0, z1))
Defined Rule Symbols:
h, f, g
Defined Pair Symbols:
G
Compound Symbols:
c3
(9) SIsEmptyProof (EQUIVALENT transformation)
The set S is empty
(10) BOUNDS(O(1), O(1))